货币大写转换函数的更新

March 25,2004

<%
dim a       '要转换成大写的金额
dim atoc    '转换之后的值
Dim String1 '如下定义
Dim String2 '如下定义
Dim String3 '从原A值中取出的值
Dim I       '循环变量
Dim J       'A的值乘以100的字符串长度
Dim Ch1       '数字的汉语读法
Dim Ch2       '数字位的汉字读法
Dim nZero    '用来计算连续的零值是几个

String1 = "零壹贰叁肆伍陆柒捌玖"
String2 = "万仟佰拾亿仟佰拾万仟佰拾元角分"
nZero = 0

If InStr(1, CStr(a * 100), ".") <> 0 Then
      err.Raise 5000, , "此函数( AtoC() )只能转换小数点后有两位以内的数！"
End If

J = Len(CStr(a * 100))
String2 = Right(String2, J)                            '取出对应位数的STRING2的值

For I = 1 To J
      String3 = Mid(a * 100, I, 1)                      '取出需转换的某一位的值

      If I <> (J - 3) + 1 And I <> (J - 7) + 1 And I <> (J - 11) + 1 And I <>(J - 15) + 1 Then
         If String3 = 0 Then
            Ch1 = ""
            Ch2 = ""
            nZero = nZero + 1
         ElseIf String3 <> 0 And nZero <> 0 Then
            Ch1 = "零" & Mid(String1, clng(String3) + 1, 1)
            Ch2 = Mid(String2, I, 1)
            nZero = 0
         Else
            Ch1 = Mid(String1, clng(String3) + 1, 1)
            Ch2 = Mid(String2, I, 1)
            nZero = 0
         End If
      Else                                              '该位是万亿，亿，万，元位等关键位
         If String3 <> 0 And nZero <> 0 Then
            Ch1 = "零" & Mid(String1, clng(String3) + 1, 1)
            Ch2 = Mid(String2, I, 1)
            nZero = 0
         ElseIf String3 <> 0 And nZero = 0 Then
            Ch1 = Mid(String1, clng(String3) + 1, 1)
            Ch2 = Mid(String2, I, 1)
            nZero = 0
         ElseIf String3 = 0 And nZero >= 3 Then
            Ch1 = ""
            Ch2 = ""
            nZero = nZero + 1
         Else
            Ch1 = ""
            Ch2 = Mid(String2, I, 1)
            nZero = nZero + 1
         End If

         If I = (J - 11) + 1 Or I = (J - 3) + 1 Then    '如果该位是亿位或元位，则必须写上
            Ch2 = Mid(String2, I, 1)
         End If

      End If
      AtoC = AtoC & Ch1 & Ch2

      If I = J And String3 = 0 Then                      '最后一位（分）为0时，加上“整”
         AtoC = AtoC & "整"
      End If

Next
if a=0 then
atoc="零元整"
end if
%>